面试题7-用两个栈实现队列

题目

输入一个链表，输出该链表中倒数第k个结点。

解题

队列的特性是：“先入先出”，栈的特性是：“先入后出”。

**push：**直接push进stack1。

**pop：**当stack2 中不为空时， 在stack2 中的栈顶元素是最先进入队列的元素， 直接弹出stack2栈顶元素；如果
stack2 为空时，我们把stack1中的元素逐个弹出并压入stack2，再弹出stack2栈顶元素。

import java.util.Stack;

public class Solution {
    Stack<Integer> stack1 = new Stack<Integer>();
    Stack<Integer> stack2 = new Stack<Integer>();
    
    public void push(int node) {
        stack1.push(node);
    }
    
    public int pop() {
        if (stack2.empty()){
            while (!stack1.empty()){
                stack2.push(stack1.pop());
            }
        }
        return stack2.pop();
    }
}

总结

1. 相关题目：用两个队列实现一个栈。
2. 不能只在if语句中return，因为可能无法进入循环而没有return，除非使用的有else。
3. Java Stack 类

Stack类是一个后进先出（last in first out，LIFO）的堆栈，在Vector类的基础上扩展了5个方法。从源码（部分省略）看它提供的功能：

package java.util;

/**
 * The {@code Stack} class represents a last-in-first-out
 * (LIFO) stack of objects. It extends class {@code Vector} with five
 * operations that allow a vector to be treated as a stack. The usual
 * {@code push} and {@code pop} operations are provided, as well as a
 * method to {@code peek} at the top item on the stack, a method to test
 * for whether the stack is {@code empty}, and a method to {@code search}
 * the stack for an item and discover how far it is from the top.
 * <p>
 * When a stack is first created, it contains no items.
 *
 * <p>A more complete and consistent set of LIFO stack operations is
 * provided by the {@link Deque} interface and its implementations, which
 * should be used in preference to this class.  For example:
 * <pre>   {@code
 *   Deque<Integer> stack = new ArrayDeque<Integer>();}</pre>
 *
 * @author  Jonathan Payne
 * @since   1.0
 */
public
class Stack<E> extends Vector<E> {
    /**
     * Creates an empty Stack.
     */
    public Stack() {
    }

    /**
     * Pushes an item onto the top of this stack. This has exactly
     * the same effect as:
     * <blockquote><pre>
     * addElement(item)</pre></blockquote>
     *
     * @param   item   the item to be pushed onto this stack.
     * @return  the {@code item} argument.
     * @see     java.util.Vector#addElement
     */
    public E push(E item) {
        addElement(item);

        return item;
    }

    /**
     * Removes the object at the top of this stack and returns that
     * object as the value of this function.
     *
     * @return  The object at the top of this stack (the last item
     *          of the {@code Vector} object).
     * @throws  EmptyStackException  if this stack is empty.
     */
    public synchronized E pop() {
        E       obj;
        int     len = size();

        obj = peek();
        removeElementAt(len - 1);

        return obj;
    }

    /**
     * Looks at the object at the top of this stack without removing it
     * from the stack.
     *
     * @return  the object at the top of this stack (the last item
     *          of the {@code Vector} object).
     * @throws  EmptyStackException  if this stack is empty.
     */
    public synchronized E peek() {
        int     len = size();

        if (len == 0)
            throw new EmptyStackException();
        return elementAt(len - 1);
    }

    /**
     * Tests if this stack is empty.
     *
     * @return  {@code true} if and only if this stack contains
     *          no items; {@code false} otherwise.
     */
    public boolean empty() {
        return size() == 0;
    }

    /**
     * Returns the 1-based position where an object is on this stack.
     * If the object {@code o} occurs as an item in this stack, this
     * method returns the distance from the top of the stack of the
     * occurrence nearest the top of the stack; the topmost item on the
     * stack is considered to be at distance {@code 1}. The {@code equals}
     * method is used to compare {@code o} to the
     * items in this stack.
     *
     * @param   o   the desired object.
     * @return  the 1-based position from the top of the stack where
     *          the object is located; the return value {@code -1}
     *          indicates that the object is not on the stack.
     */
    public synchronized int search(Object o) {
        int i = lastIndexOf(o);

        if (i >= 0) {
            return size() - i;
        }
        return -1;
    }

    /** use serialVersionUID from JDK 1.0.2 for interoperability */
    private static final long serialVersionUID = 1224463164541339165L;
}

references

《剑指offer》

“Missing return statement” within if / for / while